At a school with 100? students, 33 were taking? arabic, 32 ? bulgarian, and 40 chinese. 9 students take only? arabic, 12 take only? bulgarian, and 20 take only chinese. in? addition, 14 are taking both arabic and? bulgarian, some of whom also take chinese. how many students are taking all three? languages? none of these three? languages?

The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

Let 'p' represents the number of students who take all the three languages, then

Also,

From here, we get after subtracting equation(c) from (b) that

Therefore,

and from equation (a), we find

Thus,

and

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

6.5

step-by-step explanation:

you said it was in the question

~courtney