If an object is projected upward with an initial velocity of 129129 ft per sec, its height h after t seconds is h equals negative 16 t squared plus 129 th=−16t2+129t. find the height of the object after 44 seconds.

260 feet.

Step-by-step explanation:

We have been given that an object is projected upward with an initial velocity of 129 ft per sec, its height h after t seconds is .

To find the height of object after 4 seconds, we will substitute t=4 in our given function.

Therefore, the height of the object after 4 seconds will be 260 feet.

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answer: all the values are within because it has a pattern that repeats from -6 to 4.

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