Mathematics, 29.01.2020 18:48 kayleewoodard

Ahmed wrote two numbers. the first number has a 7 in its tenths place. the second number has a 7 with a value that is 1,000 times greater than the value of the 7 in the first number. in which place is the 7 in the second number?

Answers: 3

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Answer from: neko64

The place of 7 in second number can be identified by using multiplication of number system.

The the second number 7 is on the place of the ten thousands.

Given:

The first number has a 7 in its tenth place.

As per the given question first number has 7 in its tenths place so the number would be 10 time greater than its self. Now find the number,

$7\times 10=70$

The second number has a 7 with a value that is 1,000 times greater than the value of the 7 in the first number so the number would be 1000 time greater than its self.

$7\times 1000=7000$

Thus, the the second number 7 is on the place of the ten thousands.

Learn more about multiplication of number system is here:

link

Answer from: elijahjacksonrp6z2o7

In the hundreds place.

Step-by-step explanation:

1. You know that the first number has a 7 in its tenths place. This means that it is after the decimal point. You can write is as following:

x.7

Where x represents the other digits.

2. The second number has a 7 with a value that is 1,000 times greater than the value of the 7 in the first number, this means that you can know the place of the 7 in the second number if you multiply the first number by 1,000, or in other words, move the decimal point three places to the rigth. Therefore:

x.7*1000=7xx

3. As you can see, the 7 is in the hundred place in the second number.

Answer from: Quest

what is a pre-existing condition claus?

means if you're already damaged some way when you take out a medical insurance you will not get full compensation for that injury that you already have.

Answer from: Quest

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

$a_{n}=a+(n-1)d\\ =19-5(n-1)\\=24-5n$

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

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