1.state whether the relationship between the variables in the table is a direct variation, an inverse variation, or neither. if it is a direct or inverse variation, write a function to model it.

2.how do the graphs of y=1/x and y=/5x+6

compare?

Step-by-step explanation:

Left Pane

Argument

[Left Graph]: The table should be graphed to begin with. Some people don't like that idea very much, but it is a quick way to get an answer. I  took the liberty of adding 0,0

When a line goes through 0,0 the variation in this case is a direct variation. Then general equation for a direct variation is y = k*x

K is the slope. You should get 3.

m = (y2 - y1) / (x2 - x1)

Givens

Solution

Answer

Direct variation

Right Panel

Argument

The best way to show this is to (again) graph it. [Right Graph]

The last two are asymptote where if the denominator approaches these values, the hyperbola goes upwards depending on what part of the graph being observed.

The 6 has the property of moving the graph left (x + 6). And the 5 has the property of stretching the graph up and down. Note the word used is stretched not moved.

answer: i oofed

step-by-step explanation:

oofed=wow

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)