Two solutions of differently concentrations of acid are mixed creating 40 ml of a soul union that is 32% acid one-quarter of the soulutiob is made up of 20% acid soulution. the remaining three quarters is made up of a solution of unknown concentration c. which equation can be used to determine c, the unknown.

Three quarters (30 ml) is made up of a 36% acid solution.

Step-by-step explanation:

Since we have given that

Total amount of solution = 40 ml

One- quarter of the solution is given by

Three-quarter of the solution is given by

According to question, we have

10 ml of solution is made up of = 20% of acid solution

30 ml of solution is made up of = say 'c ' of acid solution

40 ml of solution is made up of = 32 % of acid solution

So, our equation becomes,

Hence,  three quarters (30 ml) is made up of a 36% acid solution.

it should be a and d. lmk if i'm wrong xd