Which of the following equations has both 2 and -4 as solutions

a x2 + 6x + 8 = 0
b x2 - 2x - 8= 0
c x2 + 2x - 8 = 0
d x2 - 2x + 8 = 0

Problem A; has -2 and -4 as solutions, so this is incorrect.

Problem B; has 4 and -2 as solutions; so this is incorrect.

Problem D; has 1 + √7i and 1 - √7i as solutions, this is also incorrect

Which leaves us to problem C;

Problem C;

Factor x^2 + 2x - 8

(x - 2)(x + 4) = 0

Solve for x

x = 2, -4

Your answer is C. x2 + 2x - 8 = 0

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