find the slope of this equation:
6x+6=−4y

the slope is -3/2

Step-by-step explanation:

We need to get the equation in the form

y = mx +b where m is the slope and b is the y intercept

6x+6 = -4y

Divide by -4

-6x/-4 +6/-4 = -4y/-4

-3/2 x -3/2 = y

The slope is -3/2 and the y intercept is -3/2

-3/2 is your slope

Step-by-step explanation:

Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Divide -4 from both sides.

(-4y)/-4 = (6x + 6)/-4

y = (6x)/-4 + (6)/-4

y = (-3/2)x - (3/2)

Note the formula: y = mx + b, in which m = slope, and b = y-intercept.

-3/2 is your slope.

~

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: