Aschool conference room can seat a maximum of 83 people. the principal and two counselors need to meet with the school’s student athletes to discuss eligibility requirements. if each student must bring a parent with them, what is the maximum number of students that can attend each meeting? a. 41 students b. 40 students c. 80 students d. 83 students

b. 40 students

Step-by-step explanation:

This scenario is so true at my school XD

But a total of 83 people. Actually 80 since the principal and two counselors are present.

Then you divide by one since it asks they must bring "a" parent. So 80 students / 1 parent = 80 students. But since parents are included you would need 40 parents at max, which corresponds to 40 students at max.

So that's your answer :D

Option (b) is correct.

Thus,  40 is the maximum number of students that can attend each meeting.

Step-by-step explanation:

 Given :  A school conference room can seat a maximum of 83 people. The principal and two counselors need to meet with the school’s student athletes to discuss eligibility requirements.

Also, given :  each student must bring a parent with them.

Total seats of school conference room is filled by principal  ,  two counselors + students and their parents.

Thus, 83 = 1 principal + 2 counselors + students + parents.

⇒  students + parents = 83 - 3

⇒  students + parents = 80

Given one student must bring one parent with them so number of students and parents must be equal. Let it be x,

⇒ x + x = 80

⇒ 2x = 80

⇒ x = 40

Thus,  40 is the maximum number of students that can attend each meeting.

Thus, option (b) is correct.

ce pula mea vrei ma

step-by-step explanation:

gayule

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.