What two consecutive odd integers have a sum of -28

-15 and -13

Step-by-step explanation:

Assume that x is an odd integer, if we added one to this integer it would become even and then if we added one again it would become odd again. With this said

x --> first odd integer

x + 2 --> second odd integer

We want these integers to equal -28 so:

x + (x + 2) = -28

2x + 2 = -28

2x = -30

x = -15

Then we plug in x back into (x+2) to get the second integer

-15 + 2 = -13

And to check

-15 + -13 = -28

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.