anyone? find the second, fifth, and ninth terms of a sequence where the first term is 65 and the common difference is -7. 72, 93, 121 72, 79, 86 58, 37, 9 58, 51, 44

58, 37, 9

Step-by-step explanation:

Given:

First term a₁ = 65 and common difference d = - 7

This sequence is arithmetic series and formula for calculating n-th term is:

aₙ = a₁ + (n-1) d

Accordingly

The second term is:

a₂ = 65 + (2-1) (-7) = 65 - 7 = 58

a₂ = 58

The fifth term is:

a₅ = 65 + (5 - 1) (-7)  = 65 + 4 · (-7) = 65 - 28 = 37

a₅ = 37

The ninth term is:

a₉ = 65 + (9 - 1) (-7) = 65 + 8 · (-7) = 65 - 56 = 9

a₉ = 9

God with you!!!

c

Step-by-step explanation:

2/5

step-by-step explanation:

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.