Five dinosaurs go for a walk and come across some lovely chicken wings. their names are rexy, bronto, steggy, paly, and terry. there are exactly 5 dozen wings(equal enough for each dino to have a dozen right? ); however, terry is on a diet and he only eats 6 wings. if paly eats 2 more than terry, steggy eats 4 more than paly, and bronto and rexy eat the same amount because they are really hungry from not eating all day, how many chicken wings did each dino eat?

Terry eats 6 wings, Paly eats 8 wings, Steggy eats 12 wings ,Bronto eats 17 wings and Rexy eats 17 wings

Step-by-step explanation:

Given : Five dinosaurs go for a walk and come across some lovely chicken wings. Their names are Rexy, Bronto, Steggy, Paly, and Terry.

Also given, There are exactly 5 dozen wings that is 12 × 5 = 60

Given: Terry is on a diet and he only eats 6 wings.

If Paly eats 2 more than Terry that is 6 +2 = 8 wings.

Steggy eats 4 more than Paly that is 8 + 4 = 12 wings.

Wings left = 60 - (6 + 8 + 12) = 60 - 26 =  34 wings

Bronto and Rexy eat the same amount that is they divide 34 wings in equal amount.

Wings Bronto and Rexy eats = 17 wings

Thus, Terry eats 6 wings, Paly eats 8 wings, Steggy eats 12 wings ,Bronto eats 17 wings and Rexy eats 17 wings

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752