What is the binomial expansion of (2x-3)^5

(2x)^5 - 15(2x)^4 + 90(2x)^3 - 270(2x)^2 + 405(2x) - 243

first option

Step-by-step explanation:

Exponent is 5 so the coefficients will be 6

Pascal's triangle

1

1       1

1      2      1

1      3      3      1

1       4     6      4       1

1       5      10    10    5     1

So

(2x-3)^5

= 1 (2x)^5 + 5 (2x)^4 (-3) + 10(2x)^3 (-3)^2 + 10(2x)^2 (-3)^3 + 5(2x)(-3)^4 + 1 (-3)^5

= (2x)^5 - 15(2x)^4 + 90(2x)^3 - 270(2x)^2 + 405(2x) - 243

add an image

step-by-step explanation:

the answer is 13/48

step-by-step explanation: