Acollection of coins has value of 64 cents. there are two more nickels than dimes and three times as many pennies as dimes in this collection. how many of each kind of coin are in the collection?

3 dimes, 9 pennies, and 5 nickels

Step-by-step explanation:

Call the number of dimes d. Then, we will have 3d pennies and d + 2 nickels. The value for each group is 10d, 3d, and 5d + 10. Add these to get 18d + 10. This is equal to 64 cents, as stated in the question. So, setting these equal, we get that d = 3, and there are 3 dimes, 9 pennies, and 5 nickels.

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are