In a certain city, the hourly wage of workers on temporary employment contracts is normally distributed. the mean is $15 and the standard deviation is $3. what percentage of temporary workers earn less than $12 per hour? a. 6% b. 16% c. 26% d. 36%

B. 16%

Step-by-step explanation:

In the picture attached, the standard normal distribution table is shown.

The value of Z is computed as follows:

Z = (x - μ)/σ

where x is the value of interest ( = 12), μ is the mean ( = 15) and σ is the standard deviation (= 3). Replacing:

Z = (12 - 15)/3 = -1

From the table, the probability is 0.1587, approximately equal to 16%