$5400 is? invested, part of it at 11? % and part of it at 8? %. for a certain? year, the total yield is ? $522.00. how much was invested at each? rate?

Step-by-step explanation:

Let x represent the amount invested at 11%. Then (5400-x) is the amount invested at 8%. The total interest earned is the sum of the interest amounts earned on each investment. Each of those is the product of the interest rate and the amount invested.

  (5400-x)·8% + x·11% = 522

  432 +0.03x = 522 . . . . . . . . simplify

  .03x = 90 . . . . . . . . . . . . . . . subtract 432

  90/.03 = x = 3000 . . . . . . . . divide by the coefficient of x

$3000 is invested at 11%; $2400 is invested at 8%.

what are ur choices?

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,