Moesha is (3g+1) years old and shanti is twice moesha age. find the sum of the ages of moesha and shanti in 2 years time. how old will shanti be when moeshas age in twice her present age? find how old moesha and shanti were 4 years ago if g= 5

1.  In 2 years, sum of the ages of Moesha and Shanti = 9g + 7

2.  When Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

3.  4 years ago, Moesha was 12 years old and Shanti was 28 years old if g = 5.

Step-by-step explanation:

Moesha's age = 3g + 1

It is given that Shanti's age is twice Moesha's age.

So, Shanti's age = 2(3g + 1)

= 6g + 2

In 2 years time,

Moesha's age = (3g + 1) + 2 = 3g + 3

Shanti's age = (6g + 2) + 2 = 6g + 4

Hence, sum of the ages of Moesha and Shanti = (3g + 3) + (6g + 4)

= 9g + 7

Moesha's age will be twice her present age in 3g + 1 years.

After 3g + 1 years, Shanti's age will be (6g + 2) + (3g + 1) = 9g + 3 years.

= 3(3g + 1)

= thrice Moesha's present age

Hence, when Moesha's age is twice her present age, Shanti's age will be thrice Moesha's present age.

If g = 5,

Moesha's present age = 3g + 1

= 3(5) + 1

= 15 + 1

= 16

Shanti's present age = 6g + 2

= 6(5) + 2

= 30 + 2

= 32

Hence, 4 years ago, Moesha was 16-4 = 12 years old and Shanti was 32-4 = 28 years old.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.