Points j and k plotted on the coordinate grid are two vertices of rectangle jklm rectangle jklm has an area of 7 square units point j is located at 2,1 and point k is located at -5,1 each vertex of the rectangle is located at a point that has integer coordinates. what is the perimeter of rectangle jklm? (need answer asap)

Perimeter = 16 square units

Step-by-step explanation:

Since, J(2,1) and K(-5,1) are two adjacent vertices of the rectangle JKLM so the distance between these two points can give us the corresponding length or breadth of the rectangle JKLM.

Let JK be the length of rectangle JKLM

So, to find distance between the points J and K :

Now, Area of rectangle = Length × Breadth

⇒ 7 = 7 × Breadth

⇒ Breadth = 1 unit

Now, Perimeter of rectangle is given by = 2·( Length + Breadth)

⇒ Perimeter = 2·( 7 + 1)

⇒ Perimeter = 2 × 8

⇒ Perimeter = 16 square units

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.

jwjeh; hw; kjhekjhkjhwkejhkw

step-by-step explanation: