20 sharpened pencils are placed in a box containing an unknown number of unsharpened pencils suppose 15 pencils are removed at random and five of the remove pencils are sharpened based on this is it reasonable to assume that the number of unsharpened pencil is 40 explain your reasoning

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

b. astronomers

answer: the four apples you took away.

step-by-step explanation:

answer: b

step-by-step explanation: