Identify square root of 11 as either rational or irrational, and approximate to the tenths place. rational: square root of 11 ≈ 3.3 rational: square root of 11 ≈ 3.4 irrational: square root of 11 ≈ 3.3 irrational: square root of 11 ≈ 3.4

C is correct

Step-by-step explanation:

Given:

Rational number: A number in the form of division of two integers. where

Irrational number: A number can not write as division of two integers.

Example:

Therefore, is a irrational number.

Using calculator to find

Now round off to tenths place.

Hence,

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.