What is the recursive formula when given the explicit formula for the following geometric sequence? a_n=6(-8)^n-1a. a_1=-8, a_n=-6a_n-1b. a_1=6, a_n=-8a_n-1c. a_1=-8, a_n=6a_n-1d. a_1=6, a_n=8a_n-1

B.

Step-by-step explanation:

When n = 1, we have:

Now, let's compare and .

We see that:

So, finally, substituting and rearranging, we get:

In actual fact, this should be expected because the ratio between two terms in the geometric sequence is the number with the exponent!

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !