If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a point on the graph? since the function is even, the outputs of a negative x-value and a positive x-value are the same. since the function is even, the outputs of a negative y-value and a positive y-value are the same. the graph has rotational symmetry, so the point will be reflected across the y-axis. the graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.

Step-by-step explanation:

Definition:

A function is "even" when f(x) = f(−x) for all x.

Geometrically speaking, the graph face of an even function is symmetric with respect to the y-axis, meaning that its graph remains unchanged after reflection about the y-axis.

If point (6, 8) is one the points on the graph of f(x), then f(6)=8 and since function is even, you can state that f(-6)=f(6)=8. This means that point (-6,8) must also be a point on the graph. Geometrically it means that the output of a negative x-value and its opposite is the same.

correct choice is A.

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Option A

Step-by-step explanation:

A function is even if f(x) = f(-x) for all x

In other words, the function graph will be symmetrical about x=0 or y axis.

Since (6,8) and (-6,8) are two points on either side of y axis equidistant from y axis and also since f is even and one point lies on the graph the other point also lies on the graph.

Since the function is even, the outputs of a negative x-value and a positive x-value are the same.

would be the correct answer.

Option B is incorrect since output of negative y and positive y will not be same unless f is symmetrical about x axis.

Option C is incorrect as the graph is not symmetrical about a point so there cannot be rotational symmetry.

Option D is also incorrect

12cm

the answer is d

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v