The magnitude, m, of an earthquake is defined to be m=log i/s, where i is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and s is the intensity of a “standard” earthquake, which is barely detectable. which equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake? a. m=logi/10sb. m=log(10s)(it was c i just turned it in)c. m=log10s/sd. m=log10/s

The required equation is i.e. M = 1.

Step-by-step explanation:

We are given that,

Magnitude of an earthquake is defined as ,

where I is the intensity of the earthquake measured on seismograph and S is the intensity of the standard earthquake.

Since, it is given that,

The intensity of an earthquake measured is 10 times more than that of the standard earthquake.

i.e. I = 10S

So, we get,

Magnitude of an earthquake is ,

i.e. Magnitude of an earthquake is ,

i.e. Magnitude of an earthquake is M = 1.

Hence, the required equation is i.e. M = 1.

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: