D=rt solve by setting up a system of linear equations with 2 variables and 2 unknowns. a jeep and a bmw enter a highway that runs east-west at the same exit heading in opposite directions. the jeep entered the highway 30 minutes before the bmw entered the highway, and traveled 7 mph slower than the bmw. after 2 hours from the time the bmw entered the highway, the cars were 306.5 miles apart. find the speed of each car, if they were driven on cruise control

Step-by-step explanation:

Alright, lets get started.

Lets suppose, the speed of jeep is j mph

Lets suppose, the speed of BMW is b mph

Jeep traveled 7 mph slower than the BMW, means

        equation (1)

The distance covered by BMW is 2 hrs =

As jeep entered the highway 30minutes before, so jeep has advantage of 30 minutes or say half an hour.

Means traveling time for jeep is

The distance covered by Jeep in 2.5 hrs =

      equation (2)

Plugging the value of b from equation (1)

Plugging the value of j in equation (1)

Hence the speed of BMW is 72 mph and speed of jeep is 65 mph.   :   Answer

Hope it will help :)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5