Mathematics, 23.06.2019 00:30 wellllm
Given the equation of the parabola -36y=x^2 the focus of the parabola is: a)(0, 9) b) (-9, 0) c) (0, -9)
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Given the equation of the parabola -36y=x^2 the focus of the parabola is: a)(0, 9) b) (-9, 0) c) (0...
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