Ascientist launched an object upward at a speed of 32 ft per second from a height of 240 feet. the height of the object is modeled by the equation h = 240 + 32t – 16t2. after how much time will the object hit the ground? a 3 seconds b 5 seconds c 12 seconds d 20 seconds

B5 seconds

Step-by-step explanation:

h = 240 + 32t – 16t^2

When is this equation 0

0 = 240 + 32t – 16t^2

Factor out 16

0 = -16(-15-2t+t^2)

   = -16(t^2-2t-15)

What 2 numbers multiply to -15 and add to -2

-5*3 = -15

-5+3 =-2

0 = -16(t-5) (t+3)

Using the zero product property

t-5=0   t+3=0

t=5    t=-3

Since time cannot be negative

t=5 seconds

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

can you put the picture up?

step-by-step explanation: