The perimeter of a rectangle is 48 m. the width of the rectangle is 2 more than half the length. find the length and the width

Length = 14.6667

Width = 9.33333

Step-by-step explanation:

let the length be x

Width = (x/2)+2

Perimeter = 2(L+W)

Perimeter = 2(x+(x/2+2)) =48

2[(3/2)x + 2] =48

3x+4= 48

3x = 44

x =14.666667

width = (14.666667/2)+2

Width = 9.333333

PLEASE RATE BRAINLIEST

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

it will be a cylinder. with a diameter of 8 and 4 single pieces high

step-by-step explanation: