Write a polynomial function of least degree with integral coefficients that have the given zeros. 4,-1,6 f(x)=x^3-9x^2+14x+24

see explanation

Step-by-step explanation:

Given the zeros of a polynomial, say x = a, x = b, x = c

Then (x - a), (x - b), (x - c) are it's factors

and the polynomial is the product of the factors

here x = 4, x = - 1, x = 6, hence

(x - 4), (x + 1) and (x - 6) are the factors

f(x) = a(x - 4)(x + 1)(x - 6) ← a is a multiplier

let a = 1, then expanding the first pair of factors

f(x) = (x² - 3x - 4)(x - 6) ← expand out the factors

    = x³ - 3x² - 4x - 6x² + 18x + 24 ← collect like terms

    = x³ - 9x² + 14x + 24

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180