Tata darka ma 20 m siatki ogrodzeniowej. jakie wymiary w metrach, wyra¿one liczbami naturalnymi, powinien mieæ prostok¹tny warzywnik aby mo¿na by³o go ogrodziæ tak¹ siatk¹ oraz ¿eby jego pole by³o jak najwiêksze.

Hence the dimensions are 5×5 i.e. 5 meters and 5 meters such that its field would be as large as possible.

Step-by-step explanation:

Darek's dad has a 20 m fencing mesh.

Since we have to make a rectangular garden with he help of fencing the garden using this mesh, that means perimeter of this garden is 20 m.

i.e. 2( l+b)=20

also we have to fenced in such a way that its field would be as large as possible.

ie. it has the largest Area.

Now we will start from the dimensions possible as:

9×1 whose area will 9 m^2 (since Area=l×b)

Next dimension will be:

8×2 whose area will be 16 m^2

Next will be:

7×3 whose area will be 21 m^2

Next will be:

6×4 whose area will be 24 m^2

Next will be:

5×5 whose area will be 25 m^2

Next will be:

4×6 whose area will be same as of 6×4.

Hence, we get the maximum area to be 25 m^2 which is obtained when the dimensions are 5×5.

the anwers is yes.