On the set of axes below, the vertices of triangle pqr have coordinates p (-6,7) q (2,1) and r (-1,-3) what is the area of triangle pqr?

Area of ΔPQR = 25 units

Step-by-step explanation:

We will use the following formula to calculate the area of triangle ΔPQR:

A = 1/2 | x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂) | = 1/2 |(-6(1+3) +2(-3-7) +(-1)((7-1)| =

A = 1/2 |-6 · 4 + 2 · (-10) + (-1) · 6| = 1/2 | -24-20-6| = 1/2 | -50| = 1/2 · 50 = 25

A = 25 units

God with you!!!

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.