Is this the correct way to solve 2x < x + 2 ≤ 3x + 5? 2x - 3 < x + 2 -x -x x - 3 < 2 + 3 + 3 x < 5 x + 2 ≤ 3x + 5 -x -x 2 ≤ 2x + 5 -5 -5 -3 ≤ 2x /2 /2 -3/2 ≤ x -3/2 ≤ x < 5 : )

sorr dk

Step-by-step explanation:

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

investment b is an ordinary annuity with $3,909.64 in the account after one year.

step-by-step explanation: