Solve 3x2 + 4x = −5. a) the quantity of negative 2 plus or minus i square root 11 all over 3 b) the quantity of negative 2 plus or minus 4i square root 3 all over 3 c) the quantity of negative 2 plus or minus 2 square root 11 all over 3 d) the quantity of negative 2 plus or minus 4i square root 3 all over 3

Step-by-step explanation:

The given equation is

We rewrite in the general quadratic equation form to get,

By comparing to , we have

We can solve using the quadratic formula, which is given by

We substitute the values to obtain;

The correct answer is A.

A) the quantity of negative 2 plus or minus i square root 11 all over 3

Step-by-step explanation:

formula:  x = [-b ±√(b²-4ac)]/2a

The given quadratic equation be,

3x² + 4x = -5

⇒ 3x² + 4x + 5 = 0

Solution:

a = 3, b = 4 and c = 5

x = [-b ±√(b²-4ac)]/2a

x= [-4 ±√(4²-4*3*5)]/2*3

x = [-4 ±√-44]/6

x = [-4 ±2i√11]/6

x = [-2 ±i√11]/3

Therefore the correct answer is option A) the quantity of negative 2 plus or minus i square root 11 all over 3

step-by-step explanation:

hjkj

i got 10.28 but that rounds up to 10.3