The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. suppose intensity is 8000 units at a distance of 2 miles. what will the intensity be at a distance of 12 miles? round your answer to the nearest unit. a.205 units b.222 units c.248 units d.186 units

Actually the answer is B, like the original person said. I believed the comment that said it was actually C and got it wrong and it says it's B.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

answer: it's d

step-by-step explanation: