Rewrite the quadratic function in intercept or factored form f(x)=3x^2-12

f(x)= 3(x - 2)(x + 2)

Step-by-step explanation:

The given quadratic function f(x) = 3x^2 - 12

Let's factor the given function.

f(x) = 3x^2 - 3*4

Here the common factor is 3, we can take it as common factor and write the remaining terms.

f(x) = 3(x^2 - 4)

Now we can factor (x^2 - 4) using the formula (a^2 - b^2) = (a-b)(a + b)

(x^2 -4) = (x^2 - 2^2)

= (x - 2)(x + 2)

Therefore, f(x) = 3(x^2 - 2^2)

f(x)= 3(x - 2)(x + 2)

Hope this will help you to understand the concept.

Thank you.

can you post the graph?