Elena and her husband marc both drive to work. elena's car has a current mileage (total distance driven) of 15,000 and she drives 15,000 miles more each year. marc's car has a current mileage of 24,000 and he drives 11,000 miles more each year. will the mileages for the two cars ever be equal? explain

Let us set up a system of functions to describe the given situation and see if they ever intersect.

Elena has initially 15000 miles and adds 15000 per year.

we can describe it as Elena = 15000+15000(years).

Marc's equation can be given as = 24000+11000(years).

Setting both conditions equal, we get

15000+15000(years)=24000+11000(years).

Clubbing years on one side we get,

4000(years)=9000

Lets divide by 4000 on each side we get years = 2.25

Hence yes, the mileages will equal the same value (whatever it may be) in 2.25 years from the the beginning of the problem.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

42

step-by-step explanation: