2) write an equation of the line that is parallel to -x + y = 5 and passes through the point (2, -5). a) y = x - 7 b) y = x - 5 c) y = x - 3 d) y = -x - 3

Parallel lines have equal slopes.

-x + y = 5

y = x + 5

Slope = 1

y + 5 = 1(x - 2)

y + 5 = x - 2

y = x - 2 - 5

y = x - 7

Choice A

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation: