Scalar and matrix multiplication find the product:

a = 1 , b = 0 and c = 5

Step-by-step explanation:

The given matrix are,

[2  1   0]   X 1    -1    2     =   [a    b   c]

                  -1    -2   1

                   0     1    1

a = (2*1) + (1*-1) +(0*0) = 2 -1 + 0 = 1

b = (2*-1) + (1*-2) +(0*1) =-2 -2 + 0 = 0

c = (2*2) + (1*1) +(0*1) = 4 +1 + 0 = 5

Therefore the values of a,b, and c are

a= 1 , b = 0 and c = 5

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .