20 points available. i have been trying at this problem for an hour. triangle pqr is a 30-60-90 triangle with right angle q and segment pq as the longer leg. find the possible coordinates of r if p(1,6) and q(1,-3).

R=(6,-3) 60*

Q= (1,-3) 90*

P=(1,6) 30*

Step-by-step explanation:

(X, Y)

P above Q by 9

Q right angle (1,-3)

R has to be 6 to the right for 60* if it was 9 to the right it would be 30*

So the answer is (6,-3)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^