In parallelogram defg, dh = x + 1, hf = 3y, g h = 3 x − 4 , and he = 5y + 1. find the values of x and y. the diagram is not drawn to scale.

see explanation

Step-by-step explanation:

Using the property of parallelograms

• The diagonals bisect each other, hence

DH = HF and GH = HE

x + 1 = 3y and 3x - 4 = 5y + 1 ⇒ 3x = 5y + 5

Solving the 2 equations simultaneously

x + 1 = 3y → (1)

3x = 5y + 5 → (2)

rearrange (1) expressing x in terms of y

x = 3y - 1 → (3)

substitute x = 3y - 1 in (2)

3(3y - 1) = 5y + 5

9y - 3 = 5y + 5 ( subtract 5y from both sides )

4y - 3 = 5 ( add 3 to both sides )

4y = 8 ( divide both sides by 4 )

y = 2

substitute y = 2 into (3)

x = (3 × 2) - 1 = 6 - 1 = 5

Hence x = 5, y = 2

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol