Solve the equation by factoring or completing the square: x^2+4x+3=0

Factor x^2 + 4x + 3

(x + 1)(x + 3) = 0

Solve for x

Ask, when will (x + 1)(x + 3) equal zero?

When x + 1 = 0 or x + 3 = 0

Solve each of the two equations above

x = -1, -3

Answer

(x-4)(x-1) is the factor and then solve for x which is x=4 and x= 1

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer