Aline having a slope of 3/4 passes through the point (-8, 4). write the equation of this line.

4=3/4(-8)+b

Step-by-step explanation:

You have to use the equation Y=mx+b

M is your slope so 3/4

x=-8

Y=4

Then u put it into the equation and get 4=3/4(-8)+b

Hope this helps:)

STEP-BY-STEP:

I will write the equation in the slope-intercept form: y = mx + b

y = y-coordinate

m = slope

x = x-coordinate

b = y-intercept

Part 1: Substitute the knowns into the equation

y = mx + b

4 = (3/4)(-8) + b

1. Simplify

4 = -6 + b

Part 2: Solve for b

1. add 6 to both sides to get b by itself on one side

4 + 6 = b - 6 + 6

2. Simplify

10 = b

Part 3: Re-write equation with 3/4 substituted in for m and 10 substituted in for b

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)