What is the equation of a line that passes through the point (6, 1) and is perpendicular to the line whose equation is y=−2x−6 ? enter your answer in the box.

y=\frac{1}{2}x-2

Step-by-step explanation:

we are given

Line is perpendicular to y=−2x−6

we can compare it with

y=mx+b

where

m is slope

so, m=-2

so, slope is -2

Our line is perpendicular to this slope

so, slope of our line will be

now, we are given point as (6,1)

so,

now, we can use point slope form of line

we can plug values

now, we can solve for y

and we get

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.