When points a and b(-3,4) are graphed in the standard (×,y)coordinate plane the mid point about will be (1,2) what will be coordinated for point a

The coordinates for point a will be (5,0)

Step-by-step explanation:

a=(xa,ya)=?→xa=?, ya=?

b=(-3,4)=(xb,yb)→xb=-3, yb=4

Midpoind: m=(1,2)=(xm,ym)→xm=1, ym=2

1) xm=(xa+xb)/2

Replacing the known values:

1=(xa+(-3))/2

1=(xa-3)/2

Solving for xa: Multiplying both sides of the equation by 2:

2(1)=2(xa-3)/2

2=xa-3

Adding 3 both sides of the equation:

2+3=xa-3+3

5=xa

xa=5

2) ym=(ya+yb)/2

Replacing the known values:

2=(ya+4)/2

Solving for ya: Multiplying both sides of the equation by 2:

2(2)=2(ya+4)/2

4=ya+4

Subtracting 4 both sides of the equation:

4-4=ya+4-4

0=ya

ya=0

a=(xa,ya)→a=(5,0)

it is c, trust i got your back lol

step-by-step explanation: