Identify which technique would be best applied to factor the polynomial below.

A

Step-by-step explanation:

For factoring, if we can ever right a factor as   and another as    with a MINUS in between them, then the technique of "difference in two squares" is perfect!

From the problem shown, we can actually do this (shown below):

The rule is  

Thus the problem reduces to:

We have use "difference of two squares" here, hence answer choice A is right.

351.23

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v