Q=12nv2 the dynamic pressure q generated by a fluid moving with velocity v can be found using the formula above, where n is the constant density of the fluid. an aeronautical engineer users the formula to find the dynamic pressure of a fluid moving with velocity v and the same fluid moving with velocity 1.5v. what is the ratio of the dynamic pressure of the faster fluid to the dynamic pressure of the slower fluid?

Because V is raised to the second power in the original equation the velocity of the slower fluid is V^2.

The faster fluid is 1.5V, which when replaced in the equation becomes 1.5v^2.

The ratio would then be 1.5^2 which equals 2.25

The ratio is 2.25/1

Step-by-step explanation:

Fluid 1

Q = 12 n v^2

Fluid 2

Q =12 n (1.5 v)^2

    =12 n (2.25) v^2

Ratio of the faster fluid to the slower fluid

Fluid 2/Fluid 1

12 n (2.25) v^2

12 n v^2

Canceling 12 and n

(2.25) v^2

v^2

Canceling v^2

2.25

1

The ratio is 2.25/1

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."