Instructors led an exercise class from a raised rectangular platform at the front of the room. the width of the platform was (3x- 1) feet and the area was (9x^2 +6x- 3) ft^2. find the length of this platform. after the exercise studio is remodeled, the area of the platform will be (9x2+ 12x+ 3) ft^2. by how many feet will the width of the platform change?

I will not do it all. I will set it up for you.

Area = length times width

A = LW

(9x^2 + 6x - 3) = L(3x - 1)

To find L, divide both sides by (3x - 1) using long division.

After finding L, go back to A = LW but this time use the NEW AREA given to be (9x^2+ 12x+ 3).

Set Up:

(9x^2+ 12x+ 3) = LW

Note: Plug the L you found above into (9x^2+ 12x+ 3) = LW and then solve for W.

Take it from here.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

step-by-step explanation:

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