What is the equation of the line that passes through the points (2, -4) and (0, 8)? a. y = 6 x + 8 b. y = 2 x + 8 c. y = -6 x + 8 d. y = -2 x + 8 (what about this one, ? )

C

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (0, 8)

m = = = - 6

note the line passes through the point (0, 8) ⇒ c = 8

y = - 6x + 8 → C

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: