Need asap an investment banker received a bonus and invested that money in two investments. he put a certain sum of money in the first investment that returned 7% interest after one year. in the second investment he invested four times that of the first investment and got a 14% interest return after one year. if the total interest from his investments after one year was $7,245.00, find the amount invested at each interest rate.

Let x represent the amount invested at 7%. Then the amount invested at 14% is 4x, and the total return is ...

... 7%·x +14%·4x = $7245

... x(.07 +4·0.14) = $7245 . . . . . change percentages to decimals to help collect terms

... $7245/0.63 = x = $11,500 . . . . the amount invested at 7%

... 4x = 4·$11,500 = $46,000 . . . . the amount invested at 14%

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94