×((8+4/5)-3/4-2/40) i need the steps to sloving this probem so that i can explain it to my 11 year grandson

×8

Step-by-step explanation:

The sum in parentheses can be simplified by using the same denominator for all the fractions. If you notice, the 2/40 can already be simplified to 1/20, and the other denominators (5, 4) are factors of 20. This means 20 is a suitable common denominator.

Converting the fractions to have a denominator of 20, we get ...

... 4/5 = (4·4)/(5·4) = 16/20

... 3/4 = (3·5)/(4·5) = 15/20

and we already know ...

... 2/40 = (1·2)/(20·2) = 1/20

Then the sum in parentheses is ...

... (8 +16/20) -15/20 -1/20

... = 8 + (16/20 - 15/20) - 1/20

... = 8 + 1/20 - 1/20

... = 8

Note that as long as we keep the sign with the number, we can group the terms of a sum any way that is convenient.

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Often, you may find it convenient to add the negative terms before you subtract the result from the positive terms:

... = 8 + 16/20 -(15/20 +1/20) . . . . . note the -1 is factored out of the sum of negative terms so we're doing addition inside the parentheses

... = 8 + 16/20 -16/20

... = 8

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So, your result is ...

×((8 +4/5) -3/4 -2/40) = ×8

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~