The line of symmetry for the quadratic equation y = ax^2 + 8x - 3 is x = 4. what is the value of "a"?

a = - 1

Step-by-step explanation:

given a quadratic in standard form : y = ax² + bx + c : a ≠ 0

Then the x-coordinate of the vertex is

• = -

The line of symmetry passes through the parabola, hence x-coordinate is 4

y = ax² + 8x - 3 is in standard form

with a = a, b = 8 and c = - 3, hence

- = 4 ( multiply both sides by 2a

- 8 = 8a ( divide both sides by 8 )

a = - 1

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

d. you cannot tell because there are no values shown.