Acircle with center c (4,-2) contains the point d (8,1). what is the equation of the line perpendicular to the radius of the circle passing through point c?

Step-by-step explanation:

A circle with center C (4,-2) contains the point D (8,1).

Lets find out the slope of the line that contains point C  and D

Slope =

C (4,-2) is (x1,y1)  and  D (8,1) is (X2,y2)

Slope =

To get slope of perpendicular line we take negative reciprocal of 3/4 that is -4/3

the line passes throught point C

m= -4/3   , point (4,-2)

Use point slope formula

y-y1=m(x-x1)                x1= 4, y1= -2, plug in all the values

Subtract 2 on both sides

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step-by-step explanation:

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a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58